|1)_ You have a 12 volt car battery.
2)_ You connect two 6 volt 25 Watt bulbs in series across the
2a_ Bulb: 6 Volts, 25 Watts = 1.44 OHMS = 4.166
AMPS (1.44 x 4.166 = 6)
3)_ Measure the voltage across both bulbs: you will measure 6 volts
(R = 2.88 OHMS, I = 4.166 AMPS)
4)_ Now place another 6 volt 25 Watt bulb in parallel with either bulb--say
bulb closest to ground. (R = 2.16 OHMS,
I = 5.55 AMPS)
5)_ Again measure the voltage across both bulbs:
6)_ The single bulb (top) will measure 8 volts. (1.44
7)_ The two bulbs (bottom) will measure 4 volts.
8)_ Of course both voltages will equal 12 volts.
If we think of the bulbs as resistors (they are within reason), notice
that there is 6 volts dropped across one bulb in the first example.
In the second example, when the second bulb is added, more current is
made to flow, and the voltage across the single bulb went from 6 volts
to 8 volts.
In both cases the single bulb (resistor) is CONVERTING the CURRENT
a VOLTAGE: The more current, the more
Example #1: 4.166 AMPS across 1.44 OHMS = 6 Volts
Example #2: 5.55 AMPS across 1.44 OHMS = 8 Volts